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Pixel Access – Mene-Mene

Mene-Mene

Member

Posts: 1398
From: Fort Wayne, IN, USA
Registered: 10-23-2006
 		If you've looked at my vision thread you'll see I learned how to create a polygon using Sin and Cos. I was wonder how you could access each pixel within the polygon. I tried drawing a line between the points at the top and the point at the bottom. I was also wondering how to average the two colors.

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MM out-
Thought travels much faster than sound, it is better to think something twice, and say it once, than to think something once, and have to say it twice.
"Frogs and Fauns! The tournament!" - Professor Winneynoodle/HanClinto
Mene-Mene

Member

Posts: 1398
From: Fort Wayne, IN, USA
Registered: 10-23-2006
 		Hello?

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MM out-
Thought travels much faster than sound, it is better to think something twice, and say it once, than to think something once, and have to say it twice.
"Frogs and Fauns! The tournament!" - Professor Winneynoodle/HanClinto
Lazarus

Member

Posts: 1668
From: USA
Registered: 06-06-2006
 		Hello!

I suppose you could create an array - where for every array1[x,y] - the x, y contained the coordinates of a pixel.

Averaging two colors? Take their RGB values(red is (255,0,0), green(0,255,0), and blue(0,0,255), and average all three values together, I suppose.

If that would work, it'd be like(for combining red and green).
(255,0,0)
(0,255,)

(128, 128, 0)

[This message has been edited by Lazarus (edited December 22, 2006).]
Mene-Mene

Member

Posts: 1398
From: Fort Wayne, IN, USA
Registered: 10-23-2006
 		How would it store it?

Here is the code I wrote for it.


ex = 100
ey = 100
px = 100
py = 200
sightdistance = 100
FoV = 20
EnemyFacing = 270
FoVLeft = EnemyFacing - (FoV / 2)
FoVRight = EnemyFacing + (FoV / 2)
r = Sqr(Abs(ey-py)^2)+(Abs(ex-ey)^2)
theta = ATan2(py-ey,px-ex)
If theta > FoVRight And theta < FoVLeft And r < SightDistance Then
Print "I can see you!"
End If
FOVLeftX = Sightdistance * Cos(FoVLeft) + ex
FoVLeftY = Sightdistance * Sin(FoVLeft) + ey
FoVRightX = Sightdistance * Cos(FoVRight) + ex
FoVRightY = Sightdistance * Sin(FoVRight) + ey
Dim FoVX#(FoV)
Dim FoVY#(FoV)

cur = 1
For a = 1 To FoV
FoVX#(cur) = Sightdistance * Cos(FoVLeft + cur) + ex
cur = cur + 1
Next
cur = 1
For a = 1 To FoV
FoVY#(cur) = Sightdistance * Sin(FoVLeft + cur) + ey
cur = cur + 1
Next
Line ex,ey,FoVLeftX,FoVLeftY
Line ex,ey,FoVRightX,FoVRightY
cur = 2
Line FoVLeftX,FoVLeftY,FoVX(1),FoVY(1)
For a = 2 To FoV
Line FoVX(cur - 1),FoVY(cur - 1),FoVX(cur),FoVY(cur)
cur = cur + 1
Next 
cur = 2

As for averaging wouldn't it be 255,255,0?

------------------
MM out-
Thought travels much faster than sound, it is better to think something twice, and say it once, than to think something once, and have to say it twice.
"Frogs and Fauns! The tournament!" - Professor Winneynoodle/HanClinto
ArchAngel

Member

Posts: 3450
From: SV, CA, USA
Registered: 01-29-2002
 		for what language?

for C#, the getPath() method probably would be the way to go. but... I doubt your using C#

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Yes, I'm still better than you
Soterion Studios
Mene-Mene

Member

Posts: 1398
From: Fort Wayne, IN, USA
Registered: 10-23-2006
 		BB

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MM out-
Thought travels much faster than sound, it is better to think something twice, and say it once, than to think something once, and have to say it twice.
"Frogs and Fauns! The tournament!" - Professor Winneynoodle/HanClinto