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Hey Archangel, or someone else good at calculus, I need help please – That_Guy

That_Guy

Member

Posts: 30
From: TN,USA
Registered: 02-26-2005
I need to know what the anti-derivative of:
v(t) = 1 - arctan (e^t)
i know at t=1 the particle position (anti-derivative of v(t)) is at y=-1.
I need to kneed to know where it is at t=2.

I can also solve for the answer using a TI-83 calculatur.

I would like to know how to do it both analliticly(forgive my spelling) and with the calculatur.
Any help would be greatly appriecated.

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ArchAngel

Member

Posts: 3450
From: SV, CA, USA
Registered: 01-29-2002
check this one:

V(t) = t - (e^t)arctan(e^t) - (1/2)ln( 1 + (e^t)^2 ) + C

the antiderivative for the arctan is a crazy formula, something usually you want to check up on a referce chart for.

if this is wrong, correct me.

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That_Guy

Member

Posts: 30
From: TN,USA
Registered: 02-26-2005
Thanks.

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We should use crosses, not stars for are mempership level representation.